What specific parameter in the imagepng() function caused the error in the script?

The error in the script is likely caused by passing an incorrect parameter to the imagepng() function. The imagepng() function requires the image resource as the first parameter, but if a different type of data is passed instead, it can result in an error. To solve this issue, ensure that the correct image resource is passed as the first parameter to the imagepng() function.

// Incorrect parameter passed to imagepng() function causing error
// $image_data is not a valid image resource
// Correct the parameter to be $image

// Incorrect code
// imagepng($image_data, 'output.png');

// Corrected code
imagepng($image, 'output.png');