Skip to content
PHP Logo

What potential syntax errors can be identified in the code snippet?

The potential syntax errors in the code snippet are: 1. Missing semicolon at the end of the line where the $x variable is declared. 2. The use of single quotes around the variable $x within the echo statement, which will not output the value of $x but rather the literal string "$x". To fix these issues, add a semicolon at the end of the line where $x is declared and change the single quotes to double quotes within the echo statement to correctly output the value of $x.

php 
<?php
$x = 5;
echo "The value of x is: $x";
?>

Related questions