What potential issue is identified with the variable $tisch in the code?
The potential issue with the variable $tisch in the code is that it is being used without being defined or initialized. To solve this issue, we need to define or initialize the variable $tisch before using it in the code.
$tisch = ""; // Initialize $tisch variable
// Now you can use $tisch in your code
// For example:
echo $tisch;