What is the reason for assigning only one variable to $preparation in the first code snippet?

Assigning only one variable to $preparation in the first code snippet is causing the issue because it is overwriting the previous value each time the loop iterates. To solve this issue, we need to concatenate the values instead of assigning a new value. This way, we can store all the values in a single variable. 

$preparation = ''; // Initialize the variable outside the loop

foreach ($ingredients as $ingredient) {
    $preparation .= $ingredient . ', '; // Concatenate the values instead of assigning
}

$preparation = rtrim($preparation, ', '); // Remove the trailing comma and space

echo $preparation;

Keywords

PHP variable assignment code snippet programming syntax

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