What is the potential issue with the code provided in the forum thread?

The potential issue with the code provided in the forum thread is that the SQL query is vulnerable to SQL injection attacks. This is because the user input is directly concatenated into the query string without proper sanitization. To solve this issue, you should use prepared statements with parameterized queries to prevent SQL injection attacks. 

// Original code with SQL injection vulnerability
$unsafe_variable = $_POST['input'];
$sql = "SELECT * FROM table WHERE column = '$unsafe_variable'";
$result = mysqli_query($conn, $sql);

// Fixed code using prepared statements
$unsafe_variable = $_POST['input'];
$stmt = $conn->prepare("SELECT * FROM table WHERE column = ?");
$stmt->bind_param("s", $unsafe_variable);
$stmt->execute();
$result = $stmt->get_result();

Keywords

syntax error missing semicolon undefined variable PHP debugging

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