What is the main issue with the provided PHP code and JavaScript function?

The main issue with the provided PHP code and JavaScript function is that the PHP variable `$name` is not being properly passed to the JavaScript function. To solve this issue, you can echo the value of `$name` into a JavaScript variable within a script tag in the HTML output. 

<?php
$name = "John Doe";
?>
<!DOCTYPE html>
<html>
<head>
    <title>Passing PHP variable to JavaScript</title>
</head>
<body>
    <script>
        var name = "<?php echo $name; ?>";
        console.log(name);
    </script>
</body>
</html>

Keywords

PHP JavaScript syntax error undefined variable function call

Related Questions