What is the correct way to use the mysqli_error() function in the provided code?

The issue with the provided code is that the mysqli_error() function should be used after the query execution to check for any errors. To solve this issue, you need to execute the query first and then use mysqli_error() to display any errors that occurred during the query execution.

// Execute the query
$result = mysqli_query($conn, $sql);

// Check for errors
if (!$result) {
    echo "Error: " . mysqli_error($conn);
} else {
    // Process the result
}