What is the correct PHP code syntax to conditionally display a button based on a value in a MySQL database?

To conditionally display a button based on a value in a MySQL database, you can retrieve the value from the database and then use an if statement in your PHP code to determine whether to display the button or not. You can check the retrieved value against a specific condition and echo the HTML for the button only if the condition is met. 

// Assuming you have already connected to your MySQL database

// Retrieve the value from the database
$query = "SELECT button_value FROM your_table WHERE id = your_id";
$result = mysqli_query($connection, $query);
$row = mysqli_fetch_assoc($result);
$buttonValue = $row['button_value'];

// Conditionally display the button based on the value
if ($buttonValue == 'show') {
    echo '<button>Click Me</button>';
}

Keywords

PHP MySQL database conditional display syntax

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