What is the best way to display an image in PHP, regardless of the file name in the directory?

When displaying an image in PHP, regardless of the file name in the directory, you can use the header() function to set the content type of the response to image/jpeg or image/png based on the file extension. Then, you can read the image file using file_get_contents() and output it using echo. 

<?php

// Get the file path from the URL parameter
$file = $_GET['file'];

// Set the content type based on the file extension
if (pathinfo($file, PATHINFO_EXTENSION) == 'jpg' || pathinfo($file, PATHINFO_EXTENSION) == 'jpeg') {
    header('Content-Type: image/jpeg');
} elseif (pathinfo($file, PATHINFO_EXTENSION) == 'png') {
    header('Content-Type: image/png');
}

// Output the image file
echo file_get_contents($file);

?>

Keywords

PHP image display file name directory dynamic image display

Related Questions