What does the error "Parse error: parse error, unexpected $" in PHP code indicate?
The error "Parse error: parse error, unexpected $" in PHP code indicates a syntax error caused by an unexpected dollar sign ($) in the code. This typically happens when a variable is not properly declared or used in the code. To fix this error, ensure that all variables are properly declared with a dollar sign ($) before their name.
// Incorrect code causing the parse error
$variable = value;
// Corrected code
$variable = $value;
Keywords
Related Questions
- How can a beginner in PHP effectively debug and troubleshoot issues with their code, particularly when working with inherited systems?
- How can the utf8_decode() function be used to address encoding problems with special characters in PHP applications?
- What are some potential issues with using the mysql_* functions in PHP, and what are the recommended alternatives?