What are the potential reasons for mysqli_prepare() to return FALSE in PHP?
If mysqli_prepare() returns FALSE in PHP, it could be due to errors in the SQL query syntax, connection issues with the database, or insufficient permissions for the user. To solve this issue, you should check the SQL query for any errors, ensure that the database connection is established correctly, and verify that the user has the necessary permissions to execute the query.
// Example code snippet to check for errors in the mysqli_prepare() function
$conn = mysqli_connect("localhost", "username", "password", "database");
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM table WHERE column = ?";
$stmt = mysqli_prepare($conn, $sql);
if (!$stmt) {
die("Error in preparing SQL statement: " . mysqli_error($conn));
}
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