What are the potential reasons for the is_int function returning false even when the variable is set to an integer value?

The is_int function in PHP returns false when the variable is set to an integer value because PHP automatically converts variables between different types. To solve this issue, you can use the strict comparison operator (===) to check both the value and the type of the variable. This ensures that the variable is truly an integer and not just a string representation of a number. 

// Check if a variable is an integer using strict comparison
function is_int_strict($var) {
    return is_int($var) || is_string($var) && preg_match('/^-?\d+$/', $var);
}

// Test the function
$number = 42;
$is_int = is_int_strict($number);
var_dump($is_int); // Output: bool(true)

Keywords

is_int PHP variable integer value type conversion

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