What are the potential pitfalls of using a database table and a loop to generate rows for each day in a shift schedule?

One potential pitfall of using a database table and a loop to generate rows for each day in a shift schedule is that it can be inefficient and resource-intensive, especially if there are a large number of days to generate. To solve this issue, you can consider generating the rows dynamically in the application code instead of relying solely on database queries and loops.

// Sample PHP code snippet to dynamically generate rows for each day in a shift schedule

// Define the start and end dates for the shift schedule
$start_date = '2022-01-01';
$end_date = '2022-01-31';

// Calculate the number of days between the start and end dates
$interval = new DateInterval('P1D');
$daterange = new DatePeriod(new DateTime($start_date), $interval, new DateTime($end_date));

// Iterate over each day in the date range and generate the rows dynamically
foreach ($daterange as $date) {
    $shift_date = $date->format('Y-m-d');
    
    // Insert the row for the current day in the shift schedule table
    // Example database query: INSERT INTO shift_schedule (shift_date, shift_type) VALUES ('$shift_date', 'Day Shift');
}