What are some potential tricks or workarounds for passing additional values in a drop-down menu in PHP?

When working with drop-down menus in PHP, the standard method only allows for passing a single value (the selected option) to the server. However, if you need to pass additional values along with the selected option, you can use hidden input fields within a form to achieve this. By dynamically updating the hidden input fields based on the selected option, you can send multiple values to the server when the form is submitted.

<form method="post" action="process.php">
    <select name="dropdown">
        <option value="option1">Option 1</option>
        <option value="option2">Option 2</option>
        <option value="option3">Option 3</option>
    </select>
    <input type="hidden" name="additional_value1" value="">
    <input type="hidden" name="additional_value2" value="">
    <input type="submit" value="Submit">
</form>

<script>
    document.querySelector('select[name="dropdown"]').addEventListener('change', function() {
        var selectedOption = this.value;
        if (selectedOption === 'option1') {
            document.querySelector('input[name="additional_value1"]').value = 'value1';
            document.querySelector('input[name="additional_value2"]').value = 'value2';
        } else if (selectedOption === 'option2') {
            document.querySelector('input[name="additional_value1"]').value = 'value3';
            document.querySelector('input[name="additional_value2"]').value = 'value4';
        } else if (selectedOption === 'option3') {
            document.querySelector('input[name="additional_value1"]').value = 'value5';
            document.querySelector('input[name="additional_value2"]').value = 'value6';
        }
    });
</script>