What are some considerations when using the median, mean, and standard deviation in PHP to rank images based on user ratings?

When ranking images based on user ratings in PHP, it's important to consider using the median, mean, and standard deviation to accurately reflect the distribution of ratings. The median helps to account for outliers and skewed data, while the mean gives a general idea of the overall rating. The standard deviation can provide insight into the variability of ratings. 

// Sample array of user ratings for images
$userRatings = [4, 5, 3, 2, 5, 4, 5, 1, 3];

// Calculate the median
rsort($userRatings);
$mid = floor(count($userRatings) / 2);
$median = ($mid % 2 != 0) ? $userRatings[$mid] : ($userRatings[$mid - 1] + $userRatings[$mid]) / 2;

// Calculate the mean
$mean = array_sum($userRatings) / count($userRatings);

// Calculate the standard deviation
$sum = 0;
foreach ($userRatings as $rating) {
    $sum += pow($rating - $mean, 2);
}
$standardDeviation = sqrt($sum / count($userRatings));

// Rank images based on the calculated values
// Implement your ranking logic here

Keywords

median mean standard deviation user ratings ranking

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