What are common pitfalls when trying to display multiple images in a table using PHP?
Common pitfalls when trying to display multiple images in a table using PHP include not properly handling file paths, not checking if the file exists before displaying it, and not using a loop to iterate through each image. To solve this issue, you can use PHP to dynamically generate HTML code for each image within a loop. Make sure to check if the image file exists before displaying it, and properly handle the file paths to ensure the images are displayed correctly.
<?php
// Array of image file paths
$images = ['image1.jpg', 'image2.jpg', 'image3.jpg'];
echo '<table>';
foreach ($images as $image) {
if (file_exists($image)) {
echo '<tr><td><img src="' . $image . '" alt="Image"></td></tr>';
} else {
echo '<tr><td>Image not found</td></tr>';
}
}
echo '</table>';
?>
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