In what cases would PHP not recognize variables within double quotes in echo statements?

PHP may not recognize variables within double quotes in echo statements if the variable name is directly followed by a character that is considered part of the variable name. To solve this issue, enclose the variable name in curly braces within the double quotes to explicitly specify the variable name. This ensures that PHP correctly identifies and substitutes the variable within the string.

// Incorrect way without curly braces
$name = "John";
echo "Hello, $name!"; // This may not work as expected

// Correct way with curly braces
$name = "John";
echo "Hello, {$name}!"; // This will correctly output: Hello, John!