How does mysqli_stmt_prepare handle variable values with "?" placeholders in PHP applications?
When using mysqli_stmt_prepare in PHP applications, you can handle variable values with "?" placeholders by binding parameters to the statement before executing it. This ensures that the variables are properly escaped and sanitized, preventing SQL injection attacks.
// Assuming $conn is your mysqli connection
// Prepare the SQL statement with placeholders
$stmt = mysqli_prepare($conn, "SELECT * FROM users WHERE username = ?");
// Bind the parameter to the statement
mysqli_stmt_bind_param($stmt, "s", $username);
// Set the value of the parameter
$username = "example_username";
// Execute the statement
mysqli_stmt_execute($stmt);
// Get the results
$result = mysqli_stmt_get_result($stmt);
// Fetch the data
while ($row = mysqli_fetch_assoc($result)) {
// Process the data
}
// Close the statement
mysqli_stmt_close($stmt);