How can the issue of unexpected syntax error be resolved in the PHP code snippet?

To resolve the issue of unexpected syntax error in a PHP code snippet, carefully check for missing or misplaced parentheses, brackets, or quotes. Make sure all opening and closing symbols match up correctly. Additionally, ensure that semicolons are used at the end of each statement. 

// Incorrect code snippet with unexpected syntax error
$variable = 10
if ($variable > 5) {
  echo "Variable is greater than 5";
} else {
  echo "Variable is less than or equal to 5";
}

// Corrected code snippet
$variable = 10;
if ($variable > 5) {
  echo "Variable is greater than 5";
} else {
  echo "Variable is less than or equal to 5";
}

Keywords

Syntax error PHP code debugging error handling troubleshooting

Related Questions