How can the error message "Notice: Undefined variable: image" be resolved in the PHP code snippet provided?

The error message "Notice: Undefined variable: image" indicates that the variable "image" is being used without being defined or initialized in the PHP code. To resolve this issue, you can define the variable "image" before using it to prevent the error message from appearing. 

<?php
$image = ""; // Define the variable "image" to prevent the error message
if(isset($_POST['submit'])){
    $image = $_POST['image'];
    echo $image;
}
?>

Keywords

PHP error message undefined variable variable scope isset.

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