How can the error message "Invalid argument supplied for foreach()" be resolved in PHP?
The error message "Invalid argument supplied for foreach()" occurs when you try to iterate over a variable that is not an array. To resolve this issue, you should check if the variable is an array before using it in a foreach loop. You can use the is_array() function to perform this check.
if(is_array($variable)){
foreach($variable as $item){
// Your code here
}
} else {
// Handle the case when $variable is not an array
}
Keywords
Related Questions
- What potential pitfalls should be considered when converting data structures for further processing, as mentioned in the forum thread?
- What are some best practices for designing a simple website with features like registration, login, and forum using OOP PHP and MVC?
- What is the common issue with variable transmission in PHP forms?