How can the error in the line where the uncommented code starts be resolved?

The error in the line where the uncommented code starts is likely due to a syntax issue, such as a missing semicolon or a misplaced parentheses. To resolve this error, carefully review the code starting from the line where the issue occurs and check for any syntax errors. Make sure all opening and closing brackets, parentheses, and semicolons are correctly placed. 

// Uncommented code starts here
$variable = 10;
if ($variable > 5) {
    echo "Variable is greater than 5";
}

Keywords

syntax error uncommented code debugging PHP troubleshooting

Related Questions