How can the code snippet provided be improved to prevent errors like the missing $logo variable?

The issue with the provided code snippet is that the $logo variable is missing, which can cause errors when trying to access it. To prevent such errors, we can check if the $logo variable is set before trying to access it in the code. This can be done using the isset() function in PHP. 

// Check if the $logo variable is set before accessing it
if(isset($logo)) {
    echo "<img src='$logo' alt='Logo'>";
} else {
    echo "Logo not found";
}

Keywords

PHP error handling isset variable validation

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