How can the code provided be improved to display all data fields from a database table?

The issue with the current code is that it only fetches and displays one column from the database table. To display all data fields from a database table, you can modify the SQL query to select all columns using a wildcard (*) in the SELECT statement. This will retrieve all columns from the table and display them in the output. 

<?php
// Connect to the database
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database";

$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

// Select all data fields from the database table
$sql = "SELECT * FROM table_name";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // Output data of each row
    while($row = $result->fetch_assoc()) {
        foreach($row as $key => $value) {
            echo $key . ": " . $value . "<br>";
        }
        echo "<br>";
    }
} else {
    echo "0 results";
}

$conn->close();
?>

Keywords

PHP database table query display

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