How can the code be modified to account for maximum yields of minerals when calculating the optimal solution?
To account for maximum yields of minerals when calculating the optimal solution, we can modify the code to include a constraint that limits the amount of each mineral that can be used in the final solution. This can be achieved by adding additional variables and constraints to the linear programming model.
// Define the maximum yields for each mineral
$max_yields = array(
'iron' => 100,
'copper' => 150,
'gold' => 200
);
// Add constraints for maximum yields of minerals
foreach ($max_yields as $mineral => $max_yield) {
$lp->addConstraint(\Phpml\Math\LinearProgramming\Constraint::create()
->setCoefficient($mineral, 1)
->setOperator('<=')
->setValue($max_yield)
);
}
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