How can PHP be utilized to create a dropdown list of weeks that are not present in a database table for a specific scenario?

To create a dropdown list of weeks that are not present in a database table, you can generate the list dynamically using PHP. One way to achieve this is by calculating the total number of weeks in a year and then creating an array of week numbers to populate the dropdown. 

<select name="week">
    <?php
    $totalWeeks = 52; // Total number of weeks in a year
    for ($i = 1; $i <= $totalWeeks; $i++) {
        echo "<option value='$i'>Week $i</option>";
    }
    ?>
</select>

Keywords

PHP dropdown list weeks database table scenario

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