How can one optimize the code provided to correctly display only the desired results in a dropdown list based on MySQL query results in PHP?

The issue can be solved by modifying the PHP code to correctly fetch and display only the desired results from the MySQL query in the dropdown list. This can be achieved by iterating through the query results and adding them to the dropdown list options. 

<?php
// Connect to MySQL database
$connection = mysqli_connect("localhost", "username", "password", "database");

// Check connection
if($connection === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Perform a query to fetch desired results
$query = "SELECT column_name FROM table_name WHERE condition = 'desired_value'";
$result = mysqli_query($connection, $query);

// Display dropdown list with fetched results
echo "<select>";
while($row = mysqli_fetch_array($result)){
    echo "<option value='" . $row['column_name'] . "'>" . $row['column_name'] . "</option>";
}
echo "</select>";

// Close connection
mysqli_close($connection);
?>

Keywords

PHP MySQL dropdown list optimization query results

Related Questions