How can one ensure that multiple database IDs are displayed as separate options in a dropdown menu in PHP?

When displaying multiple database IDs as separate options in a dropdown menu in PHP, you can fetch the IDs from the database and loop through them to create individual option elements for each ID. This can be achieved by using a foreach loop to iterate over the database IDs and outputting them as separate options within the dropdown menu.

<select name="database_ids">
<?php
// Assuming $database_ids is an array containing the database IDs
foreach ($database_ids as $id) {
    echo "<option value='$id'>$id</option>";
}
?>
</select>