How can one ensure that external links are properly displayed in PHP without being affected by the website's URL?
When displaying external links in PHP, it's important to ensure that the links are properly formatted so they are not affected by the website's URL. To achieve this, you can use the PHP function `parse_url()` to extract the domain from the external link and then construct the link using the extracted domain.
<?php
function displayExternalLink($externalLink) {
$parsedUrl = parse_url($externalLink);
$externalDomain = $parsedUrl['scheme'] . '://' . $parsedUrl['host'];
echo '<a href="' . $externalLink . '">' . $externalDomain . '</a>';
}
$externalLink = 'https://www.example.com/page';
displayExternalLink($externalLink);
?>