How can a popup feedback form be integrated into a PHP website without opening a new window?

To integrate a popup feedback form into a PHP website without opening a new window, you can use JavaScript to create a modal popup that overlays the current page. This can be achieved by including the necessary HTML and JavaScript code within the PHP file that generates the webpage. 

<!-- Add this HTML code to create the popup feedback form -->
<div id="feedbackModal" class="modal">
  <div class="modal-content">
    <span class="close">×</span>
    <h2>Feedback Form</h2>
    <form action="submit_feedback.php" method="post">
      <label for="feedback">Enter your feedback:</label><br>
      <textarea id="feedback" name="feedback" rows="4" cols="50"></textarea><br>
      <input type="submit" value="Submit">
    </form>
  </div>
</div>

<!-- Add this JavaScript code to show/hide the popup feedback form -->
<script>
// Get the modal
var modal = document.getElementById('feedbackModal');

// Get the <span> element that closes the modal
var span = document.getElementsByClassName("close")[0];

// When the user clicks on <span> (x), close the modal
span.onclick = function() {
  modal.style.display = "none";
}

// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
  if (event.target == modal) {
    modal.style.display = "none";
  }
}
</script>

Keywords

PHP popup feedback form integration window.

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